4x^2+1+x=4x

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Solution for 4x^2+1+x=4x equation:


Simplifying
4x2 + 1 + x = 4x

Reorder the terms:
1 + x + 4x2 = 4x

Solving
1 + x + 4x2 = 4x

Solving for variable 'x'.

Reorder the terms:
1 + x + -4x + 4x2 = 4x + -4x

Combine like terms: x + -4x = -3x
1 + -3x + 4x2 = 4x + -4x

Combine like terms: 4x + -4x = 0
1 + -3x + 4x2 = 0

Begin completing the square.  Divide all terms by
4 the coefficient of the squared term: 

Divide each side by '4'.
0.25 + -0.75x + x2 = 0

Move the constant term to the right:

Add '-0.25' to each side of the equation.
0.25 + -0.75x + -0.25 + x2 = 0 + -0.25

Reorder the terms:
0.25 + -0.25 + -0.75x + x2 = 0 + -0.25

Combine like terms: 0.25 + -0.25 = 0.00
0.00 + -0.75x + x2 = 0 + -0.25
-0.75x + x2 = 0 + -0.25

Combine like terms: 0 + -0.25 = -0.25
-0.75x + x2 = -0.25

The x term is -0.75x.  Take half its coefficient (-0.375).
Square it (0.140625) and add it to both sides.

Add '0.140625' to each side of the equation.
-0.75x + 0.140625 + x2 = -0.25 + 0.140625

Reorder the terms:
0.140625 + -0.75x + x2 = -0.25 + 0.140625

Combine like terms: -0.25 + 0.140625 = -0.109375
0.140625 + -0.75x + x2 = -0.109375

Factor a perfect square on the left side:
(x + -0.375)(x + -0.375) = -0.109375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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